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Examination Tips » Neco Gce PHYSICS Practical Answers – Nov/Dec 2018 Expo

Neco Gce PHYSICS Practical Answers – Nov/Dec 2018 Expo

By: in Examination TipsNovember 20, 2018 271 Views

IMG

VERIFIED PHYSICS PRACTICAL ANSWERS

(1aiv)
In a tabular form
Under S/N
1.0, 2.0, 3.0, 4.0, 5.0

Under y(g)
8.00, 10.00, 12.00, 14.00, 16.00

[Under yR(g)= 12.5*y]
100.00, 125.00, 150.00, 175.00, 200.00

Under X(cm)
17.60, 14.00, 11.60, 10.00, 8.70

Under XR(cm) = x * 2
35.00, 28.00, 23.20, 20.00, 17.40

Under L = 70/X
2.000, 2.500, 3.000, 3.500, 4.00

DRAW ANOTHER TABLE OF y(g) and L(cm)
Under y(g)
100.00
125.00
150.00
175.00
200.00

Under L(cm)
2.00
2.50
3.00
3.50
4.00

(1av)
DRAW THE GRAPH
(1avi)
Slope(s) = Dy/DL =
y2 – y1/L2 – L1
Where y2 = 175g, y1 = 100g
L2 = 3.5cm, L1 = 2.00cm
Slope(s) = 175 – 100/3.5 – 2

(1vii)
(PICK TWO)
(i)I ensured mass did not tourch/rest on the table
(ii)I avoided error due to parallax on metre rule
(iii)I noted zero error on metre rule
(iv)I avoided draught

(1bi)
The principal of moments state that if a body is in equilibrium,then the sum of the clockwise moments about any point on the body is equal to the sum of the anticlockwise moments about the same point

(1bii)
Clockwise moment =Anti clockwise moment
10×5 = RB × 7
RB= 10×5/7
RB=50/7
RB=7.14
RA + RB=10
RA+7.14 =10

RA=10 – 7.14 =2.86N

(3a)
In a tabular form
Under S/N
1, 2, 3, 4, 5, 6

Under R(ohms)
5.0, 10.0, 15.0, 20.0, 25.0, 30.0

Under X(cm)
33.00, 49.50, 60.00, 67.00, 71.00, 74.50

Under K = 100 -X(cm)
67.00, 50.50, 40.00, 33.00, 29.00, 25.50

Under Y = x/k
0.4925, 0.9802, 1.5000, 2.0303, 2.4483, 2.9216

(3avi)
DRAW THE GRAPH

(3avii)
Slope
R2 – R1/y2 -y1
= 20 – 5/2.0 – 0.5
= 15/1.5
=10.0 ohms

(3viii)
(Pick two)
(Precaution)
(i)I would ensure that the key is opened when circuit is not in use to avoid the cell being used up
(ii)I would ensure that the electrical wires are tightly connected
(iii)I would ensure clean terminals

(3bi)
Lost volt is the voltage lost due to the internal resistance of a cell.
It is measured in volts

(3bii)
E= I(R+r)
4=I(2+0.5)
4=2.5I
I=4/2.5
I=1.6A

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